Please help me determine the answer to this question!!

Answer:[tex]x^2-3x-4=(x-4)*(x+1)[/tex][tex]x^2-6x+8=(x-4)*(x-2)[/tex]LCD= (x-4)*(x+1)*(x-2)Step-by-step explanation:Rewrite the first denominator in factor form, noticing that two numbers which multiplied gives you the last term of the trinomial (-4), and which combined give you the coefficient of the middle term (-3) are: "-4" and "1". Use these numbers to split the middle term as follows:[tex]x^2-3x-4=x^2-4x+x-4=x(x-4)+(x-4)\\x^2-3x-4=(x-4)*(x+1)[/tex]Analize similarly the polynomial in the second denominator, noticing that two numbers which multiplied gives you the last term of the trinomial (8), and which combined give you the coefficient of the middle term (-6) are: "-4" and "-2". Use these numbers to split the middle term as follows:[tex]x^2-6x+8=x^2-4x-2x+8=x(x-4)-2(x-4)\\x^2-6x+8=(x-4)*(x-2)[/tex]So now you have all the factors that are needed to build the "Least Common Denominator": (x-4), (x+1), and (x-2)