MATH SOLVE

3 months ago

Q:
# Which is the equation of a parabola with a directrix at y = −3 and a focus at (5, 3)? y = 1/12 (x-5)^2 y = -1/12 (x-5)^2 y = 1/12 (x+5)^2 y = -1/12 (x--+5)^2

Accepted Solution

A:

Answer:y = 1/12 (x − 5)²Step-by-step explanation:We can solve this graphically without doing calculations.The y component of the focus is y = 3. Since this is above the directrix, we know this is an upward facing parabola, so it must have a positive coefficient. That narrows the possible answers to A and C.The x component of the focus is x = 5. Since this is above the vertex, we know the x component of the vertex is also x = 5.So the answer is A. y = 1/12 (x−5)².But let's say this wasn't a multiple choice question and we needed to do calculations. The equation of a parabola is:y = 1/(4p) (x − h)² + kwhere (h, k) is the vertex and p is the distance from the vertex to the focus.The vertex is halfway between the focus and the directrix. So p is half the difference of the y components:p = (3 − (-3)) / 2p = 3k, the y component of the vertex, is the average:k = (3 + (-3)) / 2k = 0And h, the x component of the vertex, is the same as the focus:h = 5So:y = 1/(4×3) (x − 5)² + 0y = 1/12 (x − 5)²